Population proportion, p = 0.46
Sample size, n = 76
Standard error of the proportion is, se =
= 0.0572
Probability that the sample proportions of households is more than 0.38 is,
P[p > 0.38] = P[z > (0.38 - 0.46) / 0.0572]
= P[z > -1.3986]
= 0.9190 (Rounding to 4 decimal places)
A Food Marketing Institute found that 46% of households spend more than $125 a week on...
A Food Marketing Institute found that 34% of households spend more than $125 a week on groceries. Assume the population proportion is 0.34 and a simple random sample of 362 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is less than 0.35? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations. o.5675* (Enter your answer as...
A Food Marketing Institute found that 42% of households spend more than $125 a week on groceries. Assume the population proportion is 0.42 and a simple random sample of 55 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is between 0.38 and 0.5? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations. Answer = (Enter your...
PLEASE SHOW ME How to do this
A Food Marketing Institute found that 34% of households spend more than $125 a week on groceries. Assume the population proportion is 0.34 and a simple random sample of 362 households is selected from the population. What is the probability that the sample proportion of households spending more than S125 a week is less than 0.35? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach...
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PLEASE SOLVE BOTH AND SHOW WORK.
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A Food Marketing Institute found that 27% of households spend more than $125 a week on groceries. Assume the population proportion is 0.27 and a simple random sample of 422 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is less than 0.26? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approch and calculations. Answer ( places.) (Enter your...