Question

2. (20 points) Answer the following questions based on the given ground state electron configurations Ne]3S23p, [Ne]3S2?3p*, [Ne]3S?3p* a) Identify the above elements b) Arrange the element in order of decreasing atomic radius. Explain your reasoning in complete sentences c) Arrange the elements in order of increasing first ionization energy. Explain your reasoning in complete sentences. (Hint: be careful with the exceptions) d) In one of the element, there is a huge jump between the third ionization energy and the fourth ionization energy. Identify this element. Explain your reasoning in complete sentences.

Answer 1

U Answers we are gueses by following electronic configurations (a) [ne] 382 30th (6) c Ne] 312 3p² ( [re] BA²3PH » from quien electronic configuration dato [Ne 1 38 3p is Aluminium [ne] 32 33 is Phosphorus, and a [ae] 312 314 is Sulphun (6 or As we know that increases in a number of electron in a particular t shell result in decreases it atomic radie so our expected order must be 1 1 1 1 Al> p >S But its wronge The wright order is PY Al x s. 195pm 149pm 100pm And this all happen bz of stability of 3p² ortital of 1 I 1 ball filled Phosphorus -
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جماعهمعصمصعد سسسلمتلصلاحيا energy - Al<P<S usually atomic radius a l - ionization enthalphy/ But in case o Al & L Phosphorus have greater atomic radi thah Aluminuim even then it have more ionization enthalphy. This all of because half filled 3p3 orbital - of phosphorus. Due to this it have more symetry & Less exchange enthalphy which result in greater unization enthophy that Aluminium. (d) Aluminium is that huge jumb blw . element third & having forth wnization enthalphy electronic infiquistion of Ali 12, 292 206 -3,82 _3p Al3+ [Mel - Allt 102 28² aps so it bowmen so hard to make out e fum Abellafte Allisminius get noble gas configuration
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