force required = 0.5 pAv^2
where p = density of water
A = cross sectional area
v = velocity
F = 0.5*1000*pi*0.02^2*10^2
= 62.83 N
so the force required by fireman = 62.83 N
for the center of mass. .8.39 A fire hose 4.00 cm in diameter is capable of...
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