When forming barium sulfate from copper sulfate, 6M HCL is added in order to
A. |
prevent Ba(OH)2 from forming |
|
B. |
increase the size of the Ba(OH)2 crystals |
|
C. |
lower the pH |
|
D. |
A and B |
Barium hydroxide is a weak base and as soon as it appears, it is neutralised by 6M HCl which is a strong acid. Otherwise, Ba(OH)2 being insoluble in water, will also precipitate. To prevent this you add 6M HCl.
So, first option is correct.
Comment if any problem.
When forming barium sulfate from copper sulfate, 6M HCL is added in order to A. prevent...
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0.1 mole of barium chloride?
b) 3 moles of BACL2 will react to produce how many moles of
potassium chloride?
and so on.....
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buffer is HC2H3O2/NaC2H3O2
difference in PH: big change when added to buffer. small
change when added to water. why?
why such a bug change when you add an acud or base to water
but not to butfer?
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