Question

Suppose that X N(-10, 25), i.e., X has a Normal distribution with a mean of 10 and variance of 25. (i) Compute Prob(X -10). Answer in decimal form to 3 decimal places.

Answer 1

Solution :

Given that ,

mean = $\mu$ = -10

variance = 25

standard deviation = $\sigma$ = 5

P(x < -10) = P((x - $\mu$ ) / $\sigma$ < (-10 - (-10)) / 5)

= P(z < 0)

= 0.5

Probability = 0.500