A baboon steals an apple and runs to a nearby boulder 10.0 m to its left. The baboon reaches the boulder in 1.0s with a constant acceleration of 20.0m/s^2 leftward.
What was the baboon's initial velocity when it started running to the boulder?
Answer using a coordinate system where rightward is positive.
Round the answer to two significant digits.
given that distance (s) = 10 m
time t = 1 sec , acceleration (a)= 20 m/sec^2
distance (s) = vot +(1/2)a*t2
10 = vo*1 + (1/2*20*1^2)
vo = 0 m/s
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