The answer is 1.9x10^4. But why? 2) At elevated temperatures, methylisonitrile (CH3NC) isomerizes to acetonitrile (CH3CN):...
the answer should be B apparently. Solve this by using the first order formula and don't use the slope of the line formula. I know it's the same but I would prefer to see it by the first order formula 64) At elevated temperatures, methylisonitrile (CH3NC) isomerizes to acetonitrile (CH3CN): CH3NC (g) CH33CN (g) The reaction is first order in methylisonitrile. The attached graph shows data for the reaction obtained at 198.9°C. In pressure, CHANC 30,000 s-1 10,000 20,000 Time...
The isomerization of methylisonitrile to acetonitrile is first order in CH3NC. CH3NC (g) → CH3CN (g) The rate constant for the reaction is 9.45 × 10–5 s–1 at 478 K. When the initial [CH3NC] is 0.030 M, what is the half-life of the reaction? 7. The isomerization of methylisonitrile to acetonitrile is first order in CH3NC. CH3NC (E) → CH3CN (2) The rate constant for the reaction is 9.45 x 10551 at 478 K. When the initial (CH3NC) is 0.030...
The isomerization of methylisonitrile to acetonitrile CH3NC(g) → CH3CN(g) is first order in CH3NC. The rate constant for the reaction is 9.45 * 10-5 5-1 at 478 K. The half-life of the reaction when the initial (CH3NC) is 0.030 mol L-1 is A) 1.06 * 104 B) 5.29* 103 C) 3.53E * 105 D) 7.33 103 E) 1.36 * 10-4
The isomerization of methylisonitrile to acetonitrile CH3NC(g) → CH3CN(g) is first order in CH3NC. The half-life of the reaction is 8.42 × 10-2 at 575 K. The rate constant when the initial [CH3NC] is 0.030 mol L-1 is ________ s-1.
only questions number: #3,6,8,16,19,22 Δι CH 122 - Practice Problems for Chapter 12 Do NOT use this problem set solely as test preparation. This problem set does NOT cover everything that we have discussed in class. You will still need to study class materials in order to do well on the learning assessment. 1. Of the following all are valid units for a reaction rate except A. moll B. M/S C. molhr D.g's E.molle 2. Which one of the following...
4) At elevated temperatures, dinitrogen pentoxide decomposes to nitrogen dioxide and oxygen: 2N2O3(g) - ANO, (2) + O2(g) Write the general rate expression using all chemical species: 5) Ar elevated temperatures, dinitrogen pentoxide decomposes to nitrogen dioxide and oxygen: 2N,Os(8) ANO, (g) + O, (g) When the rate of formation of NO, is 5.5 x 10-M/s, the rate of decomposition of No, is M/s. 6) . A[NH 1 = a[Nal = +2H2] = + Write the balanced equation for a...