the function f is contiuous on the closed interval [0,2]
Homework Answers
the closed interval [0,2] and has the values given in the table below. The equation f(x)=1/2 must have at least two solutionson the interval [0,2] if k= 0,1,2,3, or 1/2?
Take the function f(x) = 1/2
Notice that it always equals 1/2
In order for it to have more than two solutions, k MUST equal 1/2. Since f(x) = 1/2 no matter what, the only "multiple" solutions arestill 1/2.
k = 1/2
4. The function f is continuous on the closed interval (-2, 1). Some values of f...
4. The function f is continuous on the closed interval (-2, 1). Some values of f are shown in the table below. --2 f(x) -3 -1 0 1 7 k3 The equation f(x) = 3 must have at least two solutions in the interval [-1,1) if k = a. 1 b. C. 2 CONN NICO d. 5. If k(r) is a continuous function over the interval (-2, 4) such that k(-2) = 3 and k(4) = 1, then k(2) 0...
Find a Fourier Series which converges to the following function on the interval (0,2). 2 f(z)...
Find a Fourier Series which converges to the following function on the interval (0,2). 2 f(z) = { x € [0, 1] 1 x € (1, 2] On the interval [-2, 2), draw the function to which your Fourier Series converges to.
Use a calculator to solve the equation on the interval [0,2 sin x = 0.1631 What...
Use a calculator to solve the equation on the interval [0,2 sin x = 0.1631 What are the solutions in the interval [0,2 ? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (Type your answer in radians. Round to four decimal places as needed. Use a comma to separate answers as needed.) B. There is no solution
Q1: Find the absolute maxima and minimum values of f on the given closed interval, and...
Q1: Find the absolute maxima and minimum values of f on the given closed interval, and state where those values occur. Qui som bola namin na minimum sales o a. f(x)=(x-2)3 x , (1, 10] b. f(x)=x-2 sinx,
A function is continuous on the closed, bounded interval [-2, 1] , and differentiable on the...
A function is continuous on the closed, bounded interval [-2, 1] , and differentiable on the open interval (-2,1)Given that f(-2) = 1 , and that the derivative of f is between –5 and —2 throughout the open interval, what is the least possible value of f (1) ? What is the greatest possible value of f(1) ? HINT: Since The greatest possible value of f(1) is f(1) – f(-2) f(1) – f(-2) ^ = f'(c) for some c€ (-2,...
"ind all solutions to the equation on the interval (0,2) - 2 cos sinx+1=0
"ind all solutions to the equation on the interval (0,2) - 2 cos sinx+1=0
Verify the mean value theorem for f(x)=2x^2 −3x+ 1 in the interval [0,2]
Verify the mean value theorem for f(x)=2x^2 −3x+ 1 in the interval [0,2]
5. Find ALL exact solutions in the interval [0,2 ) for the equation: v2 cos(2x) =...
5. Find ALL exact solutions in the interval [0,2 ) for the equation: v2 cos(2x) = -1
23. Let be a function defined and continuous on the closed interval (a,b). If f has...
23. Let be a function defined and continuous on the closed interval (a,b). If f has a relative maximum at cand a<c<b, which of the following statements must be true? 1. f'(c) exists. II. If f'(c) exists, then f'(c)= 0. III. If f'(c) exists, then f"(c)<0. (A) II only (B) III only (C) I and II only (D) I and III only (E) II and III only
Let f be the function given by f () = on the closed interval [-7,7]. Of...
Let f be the function given by f () = on the closed interval [-7,7]. Of the following intervals, on which can the Mean Value Theorem be applied to f? 11-1, 3 because f is continuous on (-1,3] and differentiable on (-1,3). II. [5, 7 because f is continuous on 5,7] and differentiable on (5,7). III. (1,5) because f is continuous on (1,5) and differentiable on (1,5). None © anal only
4. The function f is continuous on the closed interval (-2, 1). Some values of f are shown in the table below. --2 f(x) -3 -1 0 1 7 k3 The equation f(x) = 3 must have at least two solutions in the interval [-1,1) if k = a. 1 b. C. 2 CONN NICO d. 5. If k(r) is a continuous function over the interval (-2, 4) such that k(-2) = 3 and k(4) = 1, then k(2) 0...
Find a Fourier Series which converges to the following function on the interval (0,2). 2 f(z) = { x € [0, 1] 1 x € (1, 2] On the interval [-2, 2), draw the function to which your Fourier Series converges to.
Use a calculator to solve the equation on the interval [0,2 sin x = 0.1631 What are the solutions in the interval [0,2 ? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. (Type your answer in radians. Round to four decimal places as needed. Use a comma to separate answers as needed.) B. There is no solution
Q1: Find the absolute maxima and minimum values of f on the given closed interval, and state where those values occur. Qui som bola namin na minimum sales o a. f(x)=(x-2)3 x , (1, 10] b. f(x)=x-2 sinx,
A function is continuous on the closed, bounded interval [-2, 1] , and differentiable on the open interval (-2,1)Given that f(-2) = 1 , and that the derivative of f is between –5 and —2 throughout the open interval, what is the least possible value of f (1) ? What is the greatest possible value of f(1) ? HINT: Since The greatest possible value of f(1) is f(1) – f(-2) f(1) – f(-2) ^ = f'(c) for some c€ (-2,...
"ind all solutions to the equation on the interval (0,2) - 2 cos sinx+1=0
5. Find ALL exact solutions in the interval [0,2 ) for the equation: v2 cos(2x) = -1
23. Let be a function defined and continuous on the closed interval (a,b). If f has a relative maximum at cand a<c<b, which of the following statements must be true? 1. f'(c) exists. II. If f'(c) exists, then f'(c)= 0. III. If f'(c) exists, then f"(c)<0. (A) II only (B) III only (C) I and II only (D) I and III only (E) II and III only
Let f be the function given by f () = on the closed interval [-7,7]. Of the following intervals, on which can the Mean Value Theorem be applied to f? 11-1, 3 because f is continuous on (-1,3] and differentiable on (-1,3). II. [5, 7 because f is continuous on 5,7] and differentiable on (5,7). III. (1,5) because f is continuous on (1,5) and differentiable on (1,5). None © anal only
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