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Problem 6. (10 pts) The force of mortality for a survival model is given by He = 103. - Compute the values 20110950 20P50.5 a
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Answer #1

ux= 1/100-x + 1/100-x   

20|10q50= 20p50-20+10p50

= {(100-50-20)/(100-50) }*{(100-50-20)/(100-50)} -20 + {(100-50-10)/(100-50) }*{(100-50-10)/(100-50)}

=(9/25)-20+(16/25)

= 1-20

=-19

20p50.5 = {(100-50.5-20)/(100-50.5) }* {(100-50.5-20)/(100-50.5) }

= .5959*.5959

= 0.3552

e50    =

u=1/50=.02

e50= e-.02{1-e-.02*00}/{1-e-.02}

=e-.02/(1-e-0.02)

= 49.501666

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