2.
Initial temperature (T1) = 250 oC = (250 + 273) K = 523 K
Initial volume (V1) = 250.0 mL
Final volume (V2) = 125 mL
Let us say that the final temperature of the gas = T2
From Charles law,
V1/T1 = V2/T2
or, 250.0 mL/523 K = 125 mL/T2
or, T2 = 261.5 K
= (261.5 - 273) oC
= - 11.5 oC
Hence, the temperature at which the gas will occupy 125 mL = - 11.5 oC
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