Question

Requests for service in a service center follow a Poisson distribution with a mean of three per unit time. (a) What is the mean of time between two successive requests? (b) What is the probability that the time until the first request is less than 3 minutes? (c) What is the probability that the time between the second and third requests is greater than 5.5 time units? (d) Determine the mean rate of requests such that the probability is 0.8 that there are no requests in 0.5 time units. (e) If the service times are independent and exponentially distributed with a mean of 0.4 time units, what can you conclude about the long-term response of this system to requests?
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Answer #1

nter- arurival tine lla es ponential distnbunon / lambda 1/3 minute ence P(x <3)1-e 1/3* 3)6.63212 -lamb 2 hence Lambda 0.44 6287i don't wanna misguide you so i do whatever i completely know about question.... So i tried my best please appreciate..thanking you??

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