Question

Sulfuryl chloride (SO2Cl2) decomposes into sulfur dioxide (SO2) and chlorine (C12) according to the following chemical equation. SO2C12(g) → SO2(g) + C12() The half-life for the decomposition of sulfuryl chloride at 320 °C is 8.75 h, regardless of its initial concentration. A rigid vessel initially contains only SO2C12(g) at a pressure of 722 mmHg. What is the total pressure in the reactor, measured at 320 °C, 3.00 h after the start of the reaction? ANS: 875 mmHg

Answer 1

SO? 50,4,9 SO217) +4219) half life to/2 - 8,95h 142 is independent of initial concentration se it will be first aroor reaction because t4/2 = 0.693 K = 0.693 = 0.693 875 h +42 (K = 0.0792 ht / SO₂Cl2 SO₂ + Cl₂ t=0 722 mmngo o nora t=3h (122-0) mmHg x x for I order sx", con is given as Kt = 2.303 log do 0.0792 K x 3k = 2,303 log 722 0.103269 = log 722 x 0.103169 = 722 722-x 0.103169 722 722-2 - 1.268145 722 722-30

722-C = 569.335 Tx = 152.665 mmHg/ total pressure after 3h will be T = P20,42 +PS0₂ + Pela = [ (722-x) + x + x 7 mmHg 2 722+x = 722 +152.665 2 374.665 Ptotal = 875 mm Hg