Question

3. A 0.9L of a solution is prepared by dissolving 126.2g of NaF in it. The molecular weight of NaF is 41.9g/mol). If I took 0.13L of that solution and diluted it to 0.5, what is the molarity of the resulting solution?

• Answer to 3 significant figures
• Read about significant figures and rounding in the Helpful Resources page!
• Do not include units when reporting your answer
• Use standard notation or scientific notation as accepted by blackboard
  • e.g. 0.001 or 1E-3, not 1 x 10^^-3

4. Suppose you need 0.1L of a 0.47M solution of NiCl₂, but all you have is a solution that is a solution that is 0.21M. What volume of the solution do you need to dilute?

• Answer to 2 decimal places
• Read about significant figures and rounding in the Helpful Resources page!
• Do not include units when reporting your answer
• Use standard notation or scientific notation as accepted by blackboard
  • e.g. 0.001 or 1E-3, not 1 x 10^^-3

Answer 1

Moles of Naf man man may 126.2g 41.9 g/mol . 3.011 mol moles volume Conunbidion . : 3.ol1 mil 0.9L & debuted to 0.52 Now : 3.35 M 0.13 L of this concentrdion is taken Movie M₂ V2 v volume concentrition M> 3.35 Mx 0.13L = Maxo.5L 0.13 x 3.35 M Mri0 .5 M 0.870 Molerity: