10) KBr is salt of strong acid and strong base. So if has pH = 7
(E) is correct option
11) HA -----> H+ + A-
So [HA] doesn't equal to [H3O+] as it is weak acid
12)(B) is correct option
13) it is acidic buffer, pH = pKa + log[20/40)
pH = pKa + log(1/2) => pH = pKa - 0.30
pH <pKa (b) is correct
14) Auto -ionization of water
H2O(l) + H2O(l) <-----> H3O+(aq.) + OH-(aq.)
Kw = [H3O+][OH-] = 1.0×10-14
10. For an aqueous solution labeled "0.10 M potassium bromide," A) the pH is greater than...
1. Calculate the concentration of H3O+ for an aqueous solution with a pH of 1.2 A) 6.3 x 10-7M B ) 1.6 x 108 M. C) 1.0 x 10-14 M. D) 6.20 x 10-2 M E) 4.0 x 10-4M 2. Calculate the concentration of OH- for an aqueous solution with a pH of 13.8. A) 0.64 M B) 4.0 x 10-5M C) 1.5 x 10-5M D) 1.0 x 10-14 M E) 2.5 x 10-10 M 3. Which of the following...
12. The pK, for NH4 is 9.26. This expression refers to which of the following reactions? A. NH4+ (aq) + OH(aq) + NH3(aq) + H2O(aq) B. NH4+ (aq) + H2O(l) NH3(aq) + H30+(aq) C. H3O+(aq) + OH(aq) → 2H2O(1) D. NH3(aq) + H30+(aq) NH4+ (aq) + H2O(l) E. NH3(aq) + H2O(1) NH4+ (aq) + OH (aq)
Question 10 0/5 points A buffer solution is made such that the initial concentrations of lactic acid (HC3H5O3) and the lactate ion (C3H503) are both 0.600 M. What is the resulting pH if 0.020 mol of hydrochloric acid is added to 0.500 L of the buffer solution? (The Ky of HC3H5O3 is 1.4 x 10" 4.) HINT: Use your RICE chart! [A-] Note: pH = pka + log [HA] Ka x Ky = Kw = 1.0 x 10-14 2.92 3.80...
7. Choose the best answer for an aqueous solution labeled "0.10 M sodium hydroxide," A) the pH is greater than 7 B) the pH is less than 7 C) the pH = 1 D) the pH = 7 E) the pH = 13 8. Which one of the following salts gives an acidic aqueous solution? A) LINO3 B) CsBr C) Col2 D) Mg(SO3)2 E) NaF 9. Which one of the following salts gives a basic aqueous solution? A) Fe(NO3)3 B)...
pH units) decrease by a large amount (> 0.10 pH units) 8) For the chemical reaction NH3(aq) + HCl(aq) + NH4+ (aq) + CF (aq) the acid and conjugate base are a) HCI (acid); CI (conjugate base) b) HCI (acid); NH3 (conjugate base) c) HCl (acid); NH4* (conjugate base) d) NH3 (acid); NH4+ (conjugate base) e) NH3 (acid); CF (conjugate base)
17. From the following equilibrium process involving a weak acid (K2), derive the Henderson Hausselbach equation. (show all work) HA(aq) + H2O(lig) + H3O+(ag) + A (ag) 18. If the value of Ka for HCN is 4.9 x 10-10, calculate the equilibrium constant for CN-ag) +H2O(lig) H HCN(aq) + OH(aq) 19. Briefly justify the acidity difference in the following oxyacids: HCIO, HC102, and HC103. 20) What is the pH of a solution made by mixing 100.00 mL of 0.20 M...
Order these species by increasing concentration of H3O+ in a 1.0 M aqueous solution. (From the solution with the least hydronium concentration to the solution with the most hydronium concentration) H2CO3, NH4+, OH-, HCO3-, NH3, H2O H2CO3, NH4+, OH-, HCO3-, NH3, H2O H2O, H2CO3, NH4+, OH-, HCO3-, NH3 OH-, NH3, HCO3-, H2O, NH4+, H2CO3 None of the answer choices are correct.
Predicting pH Imagine you have a 0.125 M aqueous solution of aspirin, an acid drug with pKa = 3.5, in equilibrium. a) Estimate the pH of the solution Hint: Determine if it is an acid or base solution, weak or strong If weak acid/base, first try (H+) = /K,C, or [OH-] = K,C, b) Predict what would happen to the pH when you add more H2 Hint: First figure out what happens to the concentrations HA(aq) + H2O(0) A (aq)...
show all work Consider that 20.0 mL of 0.10 M HA (an arbitrary weak acid, Ka= 2.5 × 10−6) is titrated with 0.10 M NaOH solution. The ionization of HA in water occurs as the following. HA (aq) + H2O(l) ⇌ A (aq) + H3O (aq) The neutralization reaction between HA and NaOH can be expresses as the following. HA (aq) + NaOH (aq) NaA (aq) + H2O (l) Answer the following questions. A) What will be the initial...
Titration of 25.0 mL of 0.10 M NH3 with 0.10 M HCI 14 12 10 4 2 0 0 5 10 15 20 25 30 35 40 45 50 Volume of HCI (mL) What information is needed to determine the pH at the equivalence point? NH3(aq) + H3O (aq) -> NH4 (aq) + H2O(2) A. [NH4] and its Ka value B. [NH3] and its K, value. C. [NH3l, [NH41 and its Ka value. D. INH41, INH3l and its Kb value.