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Exam grades: Scores on a statistics final in a large class were normally distributed with a mean of 71 and a standard deviati
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Answer #1

use invnorm(perecntiile/100,0,1) function to get percentile value

a)

for 47th percentile critical value of z= -0.08
therefore corresponding value=mean+z*std deviation= 70.40

b)

for 65th percentile critical value of z= 0.39
therefore corresponding value=mean+z*std deviation= 74.08

c)

for 88th percentile critical value of z= 1.17
therefore corresponding value=mean+z*std deviation= 80.40

d)as 62% middle values are between 19 and 81 percentile

corresponding values are: 63.98 and 78.02

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