A 33.5 Ω resistor is connected to a power supply. As a result there is a current of 12.2 mA flowing through the resistor. Determine the power dissipated in the resistor in milli-watts (mW). Round your answer to three significant figures?
4990 mW?
The relation between power , current and resistance is
P = I^2 R
= ( 12.2* 10^-3)^2 (33.5)
= 4.986* 10^-3 W
rounding to three significant figure
P = 4.99 mW
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