Question

Problem 2: The second president of the US, John Adams, is accelerating in the pursuit vehicle at 6 m/s2 towards what remains of a Naval Air Station A: If the pursuit vehicle began at rest and accelerated at 6m/s2 for 15 seconds, how far did the vehicle travel and what is its new speed? B: John Adams then activates the nitro boost, increasing the acceleration to 22 m/s2, and jams the steering column with a bar to keep the vehicle moving a straight line. If the vehicle is 170 meters behind the cargo plane that is heading down the runway at 20 m/s, how long in seconds does it take for the vehicle to pass the plane and for the second US president to jump onboard?

Answer 1

A we know distance covered s = ut + 1/2 f_1 t^2 = 1/2 f_1 t^2 (because u = 0) = 1/2 times 6 times (15)^2 s = 675 m u = initial velocity = 0 (as it is initially rest) f_1 = acceleration = 6 m/s^2 t = time = 15 sec B The distance covered by car and plane must be same. For car, s^' = ut + 1/2 f_2 t^2 where u is initial velocity before acceleration at 22 m/s^2 therefore u = v_initial + f_1 t = 0 + (6 times 15) = 90 m/s therefore s^' = 90 times t + 1/2 times 22 times t^2 = 90 t + 11 t^2 f_2 = 2nd fine acceleration = 22 m/s^2 \r\n for plane s^'' = u^'' t + 1/2 f_3 t s^'' = 20 t f_3 = acceleration of plane = 0 u = initial velocity = 20 m/s By question, car has