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Constants Part A Coulombs law for the magnitude of the force F between two particles with charges Q and Q separated by a distance d is What is the net force exerted by these two charges on a third charge gs-46.5 nC placed between g and q at r-1.205 m Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures. d2 where K =扁, and 60-8.854 × 10 -12 C2/0.㎡) is View Available Hint(s) the permittivity of free space. Consider two point charges located on the x axis: one charge, J1 .-14.0 nC , is located at z.--1750 m : the second charge. 36.5 nC , is at the origin (z = 0.0000).

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Answer #1

This can be easily solved using vectors. Force on q3 due to q1 (attractive) is leftward away from origin also force on q3 due to q2 (repulsive) is leftward away from origin, both force in same direction will add up to give resultant force.

205m 0-s45) Co.545)12 1.96985 xIo N 9 (-205)2 - -1050563 xIoT N ー~ 1.969875 XI 1.0 50563M0 一-3.020438 x10-5N

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