How do I solve this x^2(x+1)-x(x+1)-6(x-1)=0 no idea how to make -6(x-1) to be 6(x+1) and factor out it. Be able to follow the comment
X2(X+1) - X(X+1) - 6(X-1) = 0
=> X3 - X - 6X + 6 = 0
=> X3 - 7X + 6 = 0
Now, we can use vanishing method to solve this.
We can notice that if we put X = 1, then the equation satisfy.
So, we can proceed like,
X2(X - 1) + X(X - 1) + -6(X - 1) = 0
=> (X - 1)(X2 + X - 6) = 0
=> (X - 1)(X2 +3X - 2X - 6) = 0
=> (X - 1){X(X +3) - 2*(X + 3)} = 0
=> (X - 1)(X + 3)(X - 2) = 0
So, the values of X is -3,1 and 2.
How do I solve this x^2(x+1)-x(x+1)-6(x-1)=0 no idea how to make -6(x-1) to be 6(x+1) and...
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