Question

4. Write the complete electronic configurations for the neutral manganese atom, Mn ion and the manganese ion in MnO' . Comment on the relationship between the colors of the MnO,' and Mnt and the electronic configurations. 5. The following reaction was performed for the determination of oxalate in the green salt: 5 CO2 (aq) + 2 MnO2 (aq) + 16 H'* (ag) -10 CO:( + 2 Mn** (aq) + 8 H:00 a. Determine the oxidation states of all atoms. b. Identify the oxidizing and reducing agents. c. Show that the total number of electrons lost by one ion is equal to the total number of electrons gained by the other. 6. Oxalate ion and carbon dioxide: a. Draw Lewis structures for the oxalate ion and for carbon dioxide. b. Estimate the angles and name the shapes around the carbon atoms in both molecules. c. What is the length of each of the carbon oxygen bonds? d. What happens at the molecular level during the reaction of: C.02 → 2 CO? 7. Solutions of potassium permanganate can also be standardized using Mohr's salt Fe(NH.) (SO.)-6H-0. The reaction equation is: 5 Fe? (aq) + 1 MnO2 (aq) + 8 H'(aq) → 5 Fe (aq) + 1 Mnº" (aq) + 4 H:01) a. If 0.958 grams of Fe(NH.)(SO.);6H2O was dissolved in 70 mL deionized water and 10 mL of sulfuric acid was added. How many moles of Fe was used? Show all work. b. The solution above was then titrated with KMnO. At the endpoint of the titration, how many moles of MnO.' will react with the Fet? c. If the initial volume of the buret was 1.75 mL and the final volume was 37.40 mL. What is the concentration, in molarity, of the KMnO, solution?

help w 4,5 & 6 plz

Answer 1

m +7 Qu. Mang neie atom - 25 (Alòmic No). Eletronio configuration - 15 852 26 352 3p45° 3d5 motion means loss of aê, remaining e =23 Electronic config. – 15h 25² 216 35² 3p € 3d5 - Mnoy Furst calculate Oxidation state of Manguese mnou x-8=-1 x+(-2) x4 = -1 [x = +7 mit ion means loss of Te remaining e = 18. Electronic confi- 15 25 206 35 ²3 po → comments on colors Mazt is Colorless, because the colour of the complex, which is due to d-d transition is not present in mn²t whereas, mnon, The O.s of mn is +7, which mean mn does not have dé, Theortically mnt complexes should not be colored But mnoy has deep purple colour because of charge Transfer from ligand 02- to the metal center (mn). This is called ligand to metal charge Transfer, - Electronic configuration of most is stable due to Half filled de orbital, and In mnoy it is stable because of full filled p-oshitel