Question

Characterizing Elements 1. Which end of the spectrum shows higher energy transitions? (Circle one) blue end red end 2. As wavelength increases, energy increases decreases 3. As frequency increases, energy increases decreases 4. The intense Lyman-a hydrogen solar emission line at 121.58 nm is strongly absorbed by O, in the stratosphere. This results in O's dissociation and the ultimate formation of ozone, O,, to form the ozone layer. a. Calculate the energy of one photon with a wavelength of 121.58 nm. b. Calculate the energy for a mole of photons of wavelength 121.58 nm. (Remember that I mole -6.022 X 10^)

Answer 1

Characterizing Elements 1. Which end of the spectrum shows higher energy transitions? (Circle one) in VIBGYOR, left to right wavelength increases, blue end red end energy decreases. E = hv 2. As wavelength increases, energy increases decreases v = frequency = c/l c = light velocity 3. As frequency increases, energy increases decreases 1 = wavelength E = hc/ 4. The intense Lyman-a hydrogen solar emission line at 121.58 nm is strongly absorbed by O, in the stratosphere. This results in O, s dissociation and the ultimate formation of ozone, O, to form the ozone layer. E = hc/ a. Calculate the energy of one photon with a wavelength of 121.58 nm. = (6.625*10^-34)*(3*10^8)/(122*10^-9) = 1.635*10^-18 joule b. Calculate the energy for a mole of photons of wavelength 121.58 nm. Enerev of 1 mole photons = E*6.02210^23 = 1.635*10^-18 *6.022*10^8 (Remember that I mole = 6.022 X 10') = 9.85*10^5 joule