Question

I found that the molar solubility of Calcium Sulfate is 0.00490 if its Ksp is 2.40x10^-5.

But I do not really know how to find the solubility of CaSO4 (136.2 g/mol) in g/mL.

Could someone also explain the different parts of this problem as well please? (solubility, molar solubility, and Ksp)

Much thanks :)

-5.9x107 Find the molar solubility (mol/L) of calcium sulfate if its Ksp = 2:40 Casoy, 7 Cacaq) + soucans K[x][y] 8 52.40xions =x² chong x= .00490 What is the solubility of CaSO4 (136.2 g/mol) in g/100 ml?!

Answer 1

Given Ksp = 2.40X1om5 Solubility equilibria of casoup can be shown as - asom (0) Calt cal.) + So, caq.) i Risp = [Geet ] [SO4?] We also have that if solubility of casoy is then [Q2+] = [302] = mol/L. s molle

tous; i. 240810155505 – Sa 12.40 xro-5 - 4090 x16 Molle : [cart] = 4.90X70-3 mol/l. . [5q, 2-3 = 4.90 810-3 mol/L. Solubility is defined as the maximum amount of solute . that can be dissolved in i particular amount of . Sowent to form a saturated sõletion. It can be expressed in different units such as mol/ g/mL ete. Solubility in mol/L means moles of solute that are required to prepare a one liter saturated solution, and solubility in g/me means amount (mass) of solute that make one me of saturated solution - Both are equivalent. We can convert one of them into another. Soubility is gml.:- , 1310 . Sa 0.00490 mol/L Antoni 0.00490 Mol : 0.00490 x 138.2 g/mol x2 mol 7000 m2 Y XL : 6.67x10-4 g/m2.