Question

Thc electric ractions and ep Is ons of tne ions on the surtoce or c mole molecules ploy a c tical role in mony biochemical reactions. n interesting co ooncnt or some of these processes匕that chemical coctions or clect on trans ers resut in ง change of the snoe of molecule, e crongng chemcel energy or electrical energy, and esulting in ง different su DCe cont gu ationond t ee ore different interactions. In this problem we ille plore the e rect o o change of configurton o D molecule on the o ce between it and an on n neg boring molecule. Considor the Clact C force between four ions on the su ace of t o large molecu es as sho n in the ngurg at the ght. The heavy black lines n a charge , the red ian in the molecule on the et hasa charge 2, and the two green malecules in the malcoulic on the left coch have cha out ofthe rame indicate bonds to 0 her atoms inthe molecule that c will not consider here. The o ple ion in the molecule 0 c. A schematic diapram of these ions is shown below indicating rdative cietances the right nas (a) Considar the fellawing image Qualitatively 【without ding calcu stion), wol calculation), woud you expect the force of the ions (ABC) on ion D to be attractive or repulsive? The force of the io (ABCy on ion D is atactive. O The force of th on (AC) on ion D is repuisivc. Submit Answer Tics 0/12 (b) Navu do the tai Lation to find the net free between {ABC) and D Express your result “ multiple of the terbinatian Submit Answer Tries 12 [c) As a result of anctrn being added to another part of the molecule on the left, the conniguration of the three ions (ABC) changes so that looks like the figure bedow, draning ion D in a br clese as shown. Without doing the calulation, will the force that (ABC) cxerts on D intrezsc, cecreass, or remain the same as it wes in part (ol The force that (ABC rts on D will remain the same. The force that (aBC) exerts on D wl decrease The force that (AS8C] exerts anDwill increase Submi Answer Ties 0/12

Answer 1

The force of the ions (ABC) on ion D is attractive.

This is because the distance of ion D from B and C is more than that between A and D. So the force will be greater for AD and D will get attracted to A.

(b)F = k q1q2/r^2

F = k (-2e)e/d^2 = -2 k e^2/d^2

Hence, F = -2 k e^2/d^2

the force in Y direction will get cancelled.

c)The force on D will decrease.