Determine the solubility of Fe(OH)2 at a pH of 9.82? how is the answer = 3.67x10^-6M...

Question

Question

Determine the solubility of Fe(OH)2 at a pH of 9.82?

how is the answer = 3.67x10^-6M ????

I keep getting 4.0x10^-9.

Please explain.

Answer 1

Answer #1

kOH), fe 2f t 20H at pH9.82 pro poH14-9.82 4.18 Log lon lo-418 - 6-6 X lo 2 f Pe + 20H 2 s 6-6 X 10 &s S6.610- 3-3 XIDS N 2 S

Answer 2

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