Question

The figure below shows a dipole. If the positive particle has a charge of 40.1 mC and the particles are 2.90 mm apart, what is the electric field at point A located 2.00 mm above the dipoles midpoint? (Express your answer in vector form.) X N/C d/2 d/2

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Answer #1

electric field at equitorial line due to dipole is given by

E = k q d / ( y^2 + d^2)^(3/2)

E = 9*10^9* 40.1*10^-3* 2.9*10^-3 / ( (2.9*10^-3)^2 + (2*10^-3)^2)^(3/2)

E = 2.394*10^13 N/C

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Comment in case any doubt, will reply for sure. Goodluck

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