Question

What mass of water (in grams) forms from the reaction of 2.36 L of hydrogen gas and 2.03 L of oxygen gas? Both gases are at 693 torr and 26.9 ^oC.

Answer 1

As long as both reactant gases are at the same and T, you can as the limiting reactant calculation with & alone so 2 H₂ +02 2H2O. 2.362 of He would react completly with 2.36x/2=1.18 htors of on, but there is more 2 prosent than that, so or is in excess and the is the limiting reactant. n=PVIRT = (693 tory) (2:36L)/(62-3636 LTorolka = 1635-48/18836.925 20.08682 mol H₂ X(26.97275-15) 008682 mol H₂) x (2 mol H₂ / 2 mol H2) X (18.015328 H/ = 1.569 H₂o.