a] centripetal acceleration a = v^2/r
r = v^2/a = 9.2^2/7.6 = 11.14 m answer
b] angular velocity = v/r = 9.2/11.14 = 0.826 rad/s
c] angular acceleration = 0
d] Period = 2pi*r/v = 2pi*11.14/9.2 = 7.61 s
e] revolution per minute = 60 /7.61 =7.88 rev/min
4. A sprinter nuns at constant speed 9 m's around a circular track with a centripetal...
A biker runs at constant speed 34 m/s around a circular track with a centripetal acceleration of magnitude 12.5 m/s^2 a) what is track's radius ? b) what is the magnitude of angular velocity of the sprinter? c) what is the magnitude of the sprinter's angular acceleration? d) how long does it take to complete one revolution this time is called "period of motion"? e) how many revolutions per minute does the sprinter make?
2. A car is driving at constant angular speed along a 20 m radius circular track. The car completes one revolution of the track in 10 seconds. Calculate: (i) The (tangent) speed of the car. 12.6 m/s (ii) The angular speed of the car. 0.63 1/s or 0.63 rad/s (iii) The centripetal acceleration of the car. 7.9 m/s2 (iv) The RPM (i.e. revolutions per minute) of the car. 6 RPM THE ANSWERS ARE IN BOLD, COULD YOU PLEASE SHOW THE...
A car travels at a constant speed around a circular track whose radius is 2.51 km. The car goes once around the track in 356 s. What is the magnitude of the centripetal acceleration of the car?
A car travels at a constant speed around a circular track whose radius is 2.65 km. The car goes once around the track in 341 s. What is the magnitude of the centripetal acceleration of the car?
A car travels at a constant speed around a circular track whose radius is 3.37 km. The car goes once around the track in 226 s. What is the magnitude of the centripetal acceleration of the car? I get 1.88 m/s^2
A car travels at a constant speed around a circular track whose radius is 3.0 km. The car goes once around the track in 420 s. What is the magnitude of the centripetal acceleration of the car? x m/s .1184 Additional Materials Section 5.2
You drive a car around a circular track of radius 50 m at a constant speed of 3 m/s, the centripetal acceleration magnitude (in m/s2 2.5 0.18 0.54 0.20
A 88 kg sprinter runs around a circular track with a radius of 28 m at a velocity of 13 m/s. What type of force causes the runner to turn and what is it's magnitude? Type of Force = Force = Newtons
when a car is going around a in a circular track with constant speed, what provides the centripetal firce necessary for circular motion
1. An 800 kg car travels around the edge of a circular track of radius 400 m. At one point, the car accelerates around the track, increasing its speed from 40 m/s to 60 m/s over the course of 5 s. At the instant that the car reaches 50 m/s find (a) its angular velocity (b) its radial acceleration, (c) the centripetal force acting on the car, (d) the tangential acceleration of the car, and (e) the magnitude of the...