Calculate the hydronium ion concentration and the pH when 15.0 mL of 0.80 M is mixed with 15.0 mL of 0.80 M ().
Concentration = M
pH =
if the two given solutions are acidic,
number of moles of one solution = 0.80M x 0.015L = 0.012 mol
number of moles of second solution = 0.80M x 0.015L = 0.012 mol
Total volume of the solution = 15.0+15.0= 30.0 mL = 0.030L
after mixing
concentration of resultant solution = 0.012 + 0.012 / 0.030
[H+] = 0.8 M
Concentration of H3O+ ion = 0.8M
[H+] = 0.8M
-log[H+] = -log(0.8)
PH = 0.097
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