13)
Oxidation state of H in reactant = +1
Oxidation state of H in product = +1
Oxidation state of S in reactant = -2
Oxidation state of S in product = 0
So, S is oxidised
Oxidation state of N in reactant = +5
Oxidation state of N in product = +2
So, N is reduced
Oxidation state of O in reactant = -2
Oxidation state of O in product = -2
Answer: c
14)
Kc is defined as concentration of product by concentration of reactant with each concentration term raised to power that is equal to its stoichiometric coefficient in balanced equation
So,
Kc = [CH4][H2S]^2 / [CS2][H2]^4
= (0.0200 * 0.0400^2) / (0.140 * 0.250^4)
= 0.0585
Answer: a
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