Question

QUESTION 3)What is the critical value of the test statistic to test the mean child mortality rate for countries in Africa is more than the mean child mortality rate for countries in South Asia?

0.59

0.299

0.126

2.015

2.35

Case Description

Corporations with international operations need to assess the risks associated with setting up and maintaining operations in different regions of the world. Consideration of the risks include considering such issues as political and economic stability. One indicator of the healthcare and quality of life in a country or region that is considered correlated with the risk and stability in the region is the child mortality rate. As a result, the healthcare and quality of care as measured by the child mortality rate in a region can impact the type and amount of investment in a region and countries within a region. The child mortality rate is the number of children 5 and under that die per thousand people in the population. The Inter-agency Group for Child Mortality Estimation (IGME) was obtained from www.childmortality.org. In 2008 the US rate was 7.6 deaths per thousand and in North America (US and Canada) the rate was 6.65 with a standard deviation of 0.68. The Excel file for this assignment has labels for the year, country name, and continent group.Lebanon 29.4 2 Liechtenst Luxembou Macedonia Mali Mexico Micronesia Moldova Montserra Myanmar New Zeala Nigeria Poland Portugal Qatar Russia Saint Kitts Samoa Saudi Arab Seychelle:s Singapore Slovak Re Somalia Surinamee Swazilan<d Switzerlar Thailand Timor-Les Tonga Turkey United Ara Uzbekista Vanuatu Venezuela Vietnam Zimbabwe 195.6 42.07 34.72 40.2 18.2 5 227.44 49.7 27.5 13.08 114.2 103 220.8 188.8 20.52 2 2 2 38.16 6 15.4 174.9 43.2 123 28.5 16.5 144.7 28.14 7 26.2 49.2 26.1 39.1 125.4NAME OF FIELD DESCRIPTION Country Name of the countries Continent /Region Countries were categories based on region into 8 continents. The coding scheme was 1- South-East Asia, 2 = South Asia, 3 Western Europe, 4 = Eastern Europe, 5 = Africa, 6- South America and Islands, 7-Oceania with Australia and New Zealand, 8-Middle East, 9-North America CMR1998 child mortality rate for 1998 CMR200:8 child mortality rate for 2008Use the provided random sample of observations to test the hypotheses that (i) the mean child mortality rate for countries in Africa is more than the mean Child mortality rate for countries in South Asia. (α-05), (ii) the mean child mortality rate for countries in Eastern Europe is more than the mean Child mortality rate for countries in the Middle East. (α ,01), (iii) the mean child mortality rate for countries in South East Asia is more than the mearn Child mortality rate for countries in Western Europe, (a-.05) by 10 per thousand.Africa2008 So-Asia2008 Mean Standard Error Median Mode Standard Deviation Sample Variance Kurtosis Skewness Range Minimum Maximum Sum 137.175 Mean 105.0175 2748.53671 Sample Variance 11411.13 Count 20 Count 4Africa2008 So-Asia2008 105.0175 2748.53671 11411.12789 4 137.175 Mean Variance Observations Hypothesized Mean 20 Difference df t Stat P(T<=t) one-tail t Critical one-tail P(T<-t) two-tail t Critical two-tailt-Test: Two-Sample Assuming Equal Variances Eastern Middle East 15.8375 15.71428571 119.382679 80.18809524 European Mean Variance Observations Pooled Variance Hypothesized Mean Difference df t Stat P(T<-t) one-tail t Critical one-tail P(T<=t) two-tail t Critical two-tail

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Answer #1

Solution:-

3) t = 0.59

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: uAfrica< uSouth Asia
Alternative hypothesis: uAfrica > uSouth Asia

Note that these hypotheses constitute a one-tailed test.

Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a two-sample t-test of the null hypothesis.

Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).

SE = sqrt[(s12/n1) + (s22/n2)]
SE = 54.6828
DF = 22

t = [ (x1 - x2) - d ] / SE

t = 0.59

where s1 is the standard deviation of sample 1, s2 is the standard deviation of sample 2, n1 is thesize of sample 1, n2 is the size of sample 2, x1 is the mean of sample 1, x2 is the mean of sample 2, d is the hypothesized difference between population means, and SE is the standard error.

The observed difference in sample means produced a t statistic of 0.59.

Therefore, the P-value in this analysis is 0.281.

Interpret results. Since the P-value (0.281) is greater than the significance level (0.05), we cannot reject the null hypothesis.

From the above test we do not have sufficient evidence in the favor of the claim that the mean child mortality rate for countries in Africa is more than the mean child mortality rate for countries in South Asia.

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