Question

QUESTION 13 22 22-10 Marks) A silver target is bombarded with electrons that have been accelerated by a 35 kilovolt (kV) For silver, the energy difference between the K and L shells is 22 kilo-electronvolt (keV), the energy difference berween the K and M shells is 25 keV. voltage. If the final kinetic energy of a scattered bombarding electron is 30 keV, what is the total energy (in keV) of the x-rays produced? (a) If the wavelength of the x ray produced as the result of the deceleration of a bombarding electron is the smallest possible, what is the final kinetic energy (in keV) of the scattered bombarding electron? (b) (e) What is the energy (in keV) of the Ky, x ray? For the same target, the accelerating voltage is now 70 kV. (d) Is the new 2 greater than, less than, or the same as the old ? (e) What is the energy (in keV) of the K, x ray? yt 15 I Page

Answer 1

be maximum plibu, - Kp ,I kame as the old