Question

QUUSUUTT 2. The following sets of reactants (all in aqueous solution) will lead to a precipitation reaction. Write the molecular, full ionic and net ionic equations for each. a) Sodium chloride and lead (ll) perchlorate Molecular: Na Clang+PldClouzlog > PbCl2ist Na (C104) Ful ionic: Natint Claq+P+3*7610+) wo >P6C1z, Nations Collage Net ionic: b) Potassium phosphate and magnesium nitrate Molecular: Kzl Pow) + Mg(NO3)2(x>K(NO3)+ Mg (pOu) Full ionic: Net ionic: Question 3. What mass of precipitate will form in Question 2a above if 150.0 mL of 0.200 M lead(11) perchlorate solution reacted with excess sodium chloride in solution? Question 4. For the reaction in 2b, how many grams of magnesium nitrate must be added to precipitate all of the phosphate anions in 125 mL of 0.34 M potassium phosphate.

Answer 1

(a) Balanced maleculer equation & 12 Nallant Pbilou) 244 PbU (3) + 2 Nalou) full gonic equation 0,2t + 2uou fag) Pb 2+ + - 1 Nat + za (क) Pbu, is) + 2Natt 2004 पा مقطع روععمنيعة | - To Pb2+ + 24 Lag write Net jonic spectator ions of awow. os Cancel - Pb U₂ Ls) equation that appear on full jonic equation. the both Il sides - males of Pollon) in 150 me as 0.20om r = = valume (L) x malarity 150 X 0.200 0.03 mal. with excess Nace One mal o s Pbillon) give one mal of Ppblle -males of Pb Uz formed = 0.03 mal Moss og Phan = - 0.038 278.1 glmal 8:34 gm

2K (Pou) aq + 3 mg (NO3)2 on 6k (NO 3) + mg (pon) Full ionic a kt tag) + 2 pouces + 3 m + (aq) + 6 Nogales - mga (PO4)₂ + bkt + 6Nog Net Jonic - 2 poy + 3mght mga (PO4)₂ اللهم و لم لم - 125 ml os 0.34 M suln Valume (L) X Conan •125 LX 0.34 M - 0.0425 mals L To ppt out - 2 mal of Kapoy we have 3 mal - Mgl No2 to add To precipitate out a mal 3 mal as mg/NO3)2 0.0425_ mal_7 3X0.0425 -0.06375 mal of Mg(NO3)2 added = 0.06375 mal Z mals Moss (gms) of manos), added = mal x 0.06375 X 9.45 gm malar mos 148.3