Question

QUESTION You have the same unknown compound in 2 test tubes. You add bromine to both, and keep one in the light and one in the dark? Only the sample in the light becomes colorless. What do you have? benzene alkyne alkane alkene QUESTION 2 How does a pi bonds differ from a sigma bonds? sigma bonds have the bonding orbitals running parallel to one another pi bonds are harder to break because they repel nucleophiles sigma bonds are easier to break pi bonds have the bonding orbitals running parallel to one another Sre Save 4 Anener Click Sove and Submit to save and submit. CNck Sae Al Anscers to save all anstcers DO g99 600 80 19 FS F4 F3 ef 8

Answer 1

Answer :- o Answer: alkane Explanatus :- Bromine is a brown Color liquid when Brz is added to an ensaturated hydrocarbon it and becomes adds to double armiple bond Colourless cd -(=d- +Bra - alkene Brown - Colorless -C Ec- + Brz aligne Brown = B Br - Colorless Benzene will undergo addity al Borz only in UV light. R-n +Brzung R-for THB colorless but R-H & Biz dark No reaction allcane Brown alkan Brown

Sigma bond is formed by end to end as denar overlapeng af atomei orbitals. ZE: @+ 20 opened Pi bonds are formed by Parallel or fideways overlafing af atencie orbital. € 878 => 8 hy By T-bond Dus to ineffections overlafing, Pi bends are weaker than Sigma bonds and hence easier to break - Answer, Pi bonds have the bonding or betals I running parallel to one another