Question

Cases in Probability

Conditional Events - Coins & Jars

Suppose there are two jars, A and B. Jar A contains 4 red and 3 blue balls. Jar B contains 2 red and 5 blue balls. Flip a coin twice and select Jar A on 2 heads. Otherwise select Jar B. Next, draw [randomly] one ball from the selected jar.

What is the probability of getting a red ball

Given a red ball was selected, what is the probability that it came from Jar A

Answer 1

$\frac{\frac{4}{28}}{\frac{4}{28}+\frac{6}{28}}=\frac{\frac{4}{28}}{\frac{10}{28}}=\frac{2}{5}$

Ans = 2/5 or 0.4

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