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Calculate the Kc for the reaction: ClO-(aq) + HAc (aq) <=> Ac- (aq) + HClO- (aq)....

Calculate the Kc for the reaction: ClO-(aq) + HAc (aq) <=> Ac- (aq) + HClO- (aq).

The answer is (1.8 x 10^-8) / (2.9 x10 ^-8), so the Ka of acetic acid divided by hypochlorous acid. How does one get there with that reaction (products over reactants)?

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Answer #1

HAL 4 AC KE 1.6X10 Hilo Ht clo erene the Efuation K 29X10 Cloe tHT 7Helo (2.8108) add the Equation HAL t CLo ACf Hlo Knet Kxk

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