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e Get help answering Molecular Given that NaBr is a product of each reaction, draw the structure of the haloalkane to be used(d) + Nucleophile SH Edit + NaBr Haloalkane ? Eel + Nucleophile + Nucleophile Edit - W o ch; + NaBr LOCH3 + NaBr Haloalkane +SH + Nucleophile Edit + NaBỊ Haloalkane

Given that NaBr is a product of each reaction, draw the structure of the haloalkane to be used (with the nucleophile specified above) to synthesize each of the compounds:

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Answer #1

Each reaction shown in the question proceed via substitution nucleophile bimolecular ( SN2) reaction.

In each case the substrates are haloalkanes which are attacked by suitable nucleophile to form the desire product .

The detail mechanism in each case is shown below.

N albalkane & Nucleophile - NaBr. From the structure of product (och it is clear that the subox hallo alle ane must be cor wh(a) Habbalkame - Nucleophile a Thus, the haloalkane should be the unckerphile should be ost. sh + NaBr a Br and Thens the rea& Nucleophile Habbalkone - non + NaBr should be hy en-Bp. Thus the halwankane should be c o . and the nucleophile Thms the reHalenkane • Nucleophane Nucleophile Ast U & Nabr. In the prodhet, the moncleophile C-SH) is on the above the site. Again we kthe bromine apr Thins it said that must be on the below the plane . halo akame is in the Bro and the so the halalkane is un

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