Question

numbers (last e) 2 Considering the energy level diagrams in the previous question, circle the correct word to complete each statement. In a phosphorus atom, the 3p orbitals are ( higher lower / equal ) in energy compared a. to the 3s orbital. b. In a phosphorus atom, the 3p orbitals are ( equal / not equal) in energy to each other. c. Phosphorus has a ( higher / lower / equal ) number of unpaired electrons than silicon. d. Silicon has a ( higher / lower / equal ) number of paired electrons than sulfur 3. For each element, complete the following table (similar to Question 1) I Element Condensed e configuration Energy level orbital diagram Quantum numbers (last e) 182

Answer 1

is ishi Soin of question-2 As per given information in question, the correct word to complete each statement.is ? Phosphosphorus atom energy order of orbitals is < 3 < 2p <3s<3p thus 3p orbitals have higher Energy than 3s b in phosphorus atorm. 3 p orbitals are degenerate orbitals (Equal Energy), thus have Same or Equal Energy Electronic configuration of phosphorus [17 LU LILIL 1377 IS2 252 Qp6 - 35² 373 unpaired es= 3 Electronic configuraton of Sin (Ne] [74] [711] C unpaired es=2 thus phosphorus have higher number of e's then si Energy bei Electronic configuration of, si- - [2 (LY 12/14/11] 64 on 152 252 226 352 3p2 Total paired e's are = 12 Electronic [] [] [2 112 11 10 Gr 11 11 is? 252 - 2p6 352 3p4 total paired eleetrons ale z14 s have higher Number of paired eleetrons.

Solution of Question 3 :- - ----- - - ---- 53. [kr]5524010525 ---- Element 23' --- Condensed e- [Ar] 4823d3 configuration --------- Energy Level 1 orbital diagram, ILALA LLLLLLLL - 1738 1L 2L II LIL IL 1L 1L 11 ha Increasing Energy 30 1L 1L 1L IL 1L 1L z - 3P зе 仙仙仙 Күмә бигъмәu! . till ads to neares 1L 1L 1L 2P Hard s e di di s p Quantum nie met me msn il me m Numbers of a Laste -Ait'ta 5 līTo til * + - - - -