Question

sure of chloroform (CHC13) and dichloromethane (CH2C12) at 298 Kare 1. Vapor pressure of chloroform (CHC13) mm Hg and 415 mm Hg respectively. (i) (i) Calculate the vapor pressure of the solution prepared by mixing 25.5 g of CHCl3 and 40 g of CH2C12 at 298 K mole fractions of each component in vapor phase. Ma = 36 es.cg Mc = 12 14 40 g

Answer 1

0 vapor pressure of Chcl3( Pines) = 200 mm Hg YOSSUT = 200 mm H " " CH2Clz Prince) = 415 mm ty molar mass of chalz (Menelz) - 119.5gr/mol nr. Chez (Marble) = 859m/mol Amount of Chels (Werelz) = 25:59m , ,CHUZ (WCHR/2) = 40gm No. of moles of CHCl3 ("CHela) = WCHCl3 Mately 25.5 mole 119.5 = 0.213 more no. of moles of Chzelz (Mchel2)= Hela) = - WCH 22 ) mchez - 40 - 85 = 0.471 mole mole fraction of CHC3 (MCHCE) = MCUC3 mchez Match 0.213 (0.213+0.471) Mchciz = 0.31

computo Mchez mole fraction of Chela (Melhely) = Michaz thanel 0.471 0.21370.471 69.0 - (Sphed) w. imlos ui, Spha to aenssoed unton = MCHCl3 x Pettels = (0.31x200) mm Hg = 62mm Hg vapor pressure of Cuzcz in soon ( Pchzuz) = Uchcete 1 Peitele =(0.69x415) Peterz = 286.35 mmHg : vapor pressure of the solution is p= Petels & Peitzua -(62+ 286:35) mm My P = 348.35 mm ing mole fraction of CHCl3 in vapor phase - PCHCl3 62 P 348.35 mole fraction of chez (CH222) = 1-0.18 = 0.82 - 348.35 = 0.18

© Total pressure (P) = 0,5 bar mole fraction of A in vapor phase (YA) = 0.35 mole fraction of A in liquid phase (MA) = 0.65 let, vapor pressure of A is PA .. Yn = w Pa = YA P =(0:35X0.5) bar 20.175 bar mole fraction of B in vapor phase (YB) = 1 - YA - 1-0:35 = 0.65 bar :- YB = Po wrPB = YBXP = (0.65X0.5) = 0.325 bar mole fraction of B in liquid phase ("B)=14A = 0.35 PA = MAPA I PB = NBP² w; po = Blue NA = 0.175 0:35 - 0.325 0.65 = 0.269 bar - vapor pressure of l e = 0.929 bar pure A is 0.269 bar B is 0.929 bar.