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2. Let X be a continuous random variable with pdf ( cx?, |a| 51, f(x) = { 10, otherwise, where the parameter c is constant (w

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TOPIC:Pdf,cdf,probability,expectation and variance.

27 The pdf of x is given as - Hx) = { cx² ; 1x141. Ey / sxsl. otherwise. @ Dince, HX) is a valid py; we, must have, Haldx=1.by Define F. (x) = P (XLX). . =cdf of x. So, we have for, -15X61; F(x) = (det) dt . = ² . [2² - (-2²). - Xt; dom, -15. We get③ we needs P(xy, ť). = 1-P ( x < Ž). - 1-F (2 [F(x) = P(x <x): as, x is continuous = 1 - ² - [ (4) + 1] (using the ed - 0.437Again, we have € (x²) - 1 x pex) dx *[T. x2. Hence, var (x) = E(X²) – 6²(x). - -(0) Tons

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