Question

An article in Nature Genetics (Vol. 34(1), 2003, pp. 85-90), Treatment-Specific Changes in Gene Expression Discriminate in Vivo Drug Response in Human Leukemia Cells, reported the study of gene expression as a function of treatments for leukemia. One group received a high dose of the drug while the control group received no treatment. Expression data (measures of gene activity) from one gene are shown in the table on the right (for all of the treated subjects and some of the control subjects). Compute the (a), (b) sample mean and (c), (d) sample standard deviation for each group separately. Round parts (a) and (c) to 2 decimal places; round parts (b) and (d) to 1 decimal place907 9 131590 6 9 8 n7137858 .1 5 2 9931432442305056534573 2411135259312111914111 7 3 4 1 2 0332797 26033 63242946572 H115-1921141 3522(a) Sample mean of High Dose 52.65 (b) Sample mean of Control T 382.7 (c) Sample standard deviation of High Dosee (d) Sample standard deviation of Control

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Answer #1
high low
16.1 297.1
134.9 491.8
52.7 1332.9
14.4 1172
124.3 1482.7
99 335.4
24.3 528.9
16.3 24.1
15.2 545.2
47.7 92.9
12.9 337.1
72.7 102.3
126.7 255.1
46.4 100.5
60.3 159.9
23.5 168
43.6 95.2
79.4 132.5
38 442.6
58.2 15.8
26.5 175.6
25.1 131.1
52.64545 382.6682
38.6046 418.5981

formula used in excel

=AVERAGE(A2:A23) =AVERAGE(B2:B23)
=STDEV(A2:A23) =STDEV(B2:B23)

a) 52.65

b) 382.67

c) 38.60

d) 418.60

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