Suppose a scheduled airline flight must average at least 62% occupancy in order to be profitable...
Suppose a scheduled airline flight must average at least 63% occupancy in order to be profitable to the airline. Occupancy rates were recorded daily for a regularly scheduled flight on each of 120 days, showing a mean occupancy per flight of 60% and a standard deviation of 10%. (a). If μ is the mean occupancy per flight and if the company wishes to determine whether or not this scheduled flight is unprofitable, give the alternative and the null hypotheses for...
2. Suppose a scheduled airline flight must average at least 60% occupancy in order to be profitable to the airline. An examination of the occupancy rate for 120 10:00 A.M. flights from Atlanta to Dallas showed a mean occupancy per flight of 58% and a standard deviation of 11%. a. If u is the mean occupancy per flight and if the company wishes to determine whether or not this scheduled flight is unprofitable, give the alternative and the null hypotheses...
To properly treat patients, drugs prescribed by physicians must have a potency that is accurately defined. Consequently, not only must the distribution of potency values for shipments of a drug have a mean value as specified on the drug's container, but also the variation in potency must be small. Otherwise, pharmacists would be distributing drug prescriptions that could be harmfully potent or have a low potency and be ineffective. A drug manufacturer claims that its drug is marketed with a...
Independent random samples of n = 150 and n = 150 observations were randomly selected from binomial populations 1 and 2, respectively. Sample 1 had 68 successes, and sample 2 had 74 successes. You wish to perform a hypothesis test to determine if there is a difference in the sample proportions P, and py: (a) State the null and alternative hypotheses. O Ho: (P1 - P2) = 0 versus Ha: (P1-P2) < 0 O Ho: (2,-) < versus H: (2,-2)...
A bottling company prints "300 ml" on its label. The quality control supervisor selects nineteen cans at random and checks them. She finds the sample mean volume to be x = 297.3 and 5 = 3.2. Do the data present sufficient evidence to indicate that the mean volume is less than that claimed on the label? (Use a = 0.05.) (a) State the null and alternative hypotheses. O Hou # 300 versus H: Il = 300 OH: < 300 versus...
A random sample of 100 observations from a population with standard deviation 63 yielded a sample mean of 111. Complete parts a through c. a. Test the null hypothesis that y 100 against the alternative hypothesis that > 100, using a 0.05. Interpret the results of the test. Ho is rejected Ho is not rejected O Interpret the results of the test. Choose the correct interpretation below. O A. There is sufficient evidence to indicate the true population mean is...
A study was conducted on the effect of an oral antiplaque rinse on plaque buildup on teeth. Twelve people whose teeth were thoroughly cleaned and polished were randomly assigned to two groups of six subjects each. Both groups were assigned to use oral rinses (no brushing) for a two-week period. Group 1, the control group, received a rinse that, unknown to the subjects, contained no antiplaque agent. Group 2 used a rinse that contained an antiplaque agent. A plaque index...
Independent random samples were selected from two quantitative populations, with sample sizes, means, and variances given below. Sample Size Sample Mean Sample Variance Population 1 2 34 45 9.8 7.5 10.83 16.49 State the null and alternative hypotheses used to test for a difference in the two population means. O Ho: (41 - H2) = 0 versus Ha: (41 - M2) > 0 Ho: (41 – 12) # O versus Ha: (H1 - H2) = 0 HO: (41 – My)...
The SAT subject tests in chemistry and physics for two groups of 13 students each electing to take these tests are given below. Chemistry Physics x = 785 x = 753 s = 115 s = 104 n = 13 n = 13 To use the two-sample t-test with a pooled estimate of o?, you must assume that the two population variances are equal. Test this assumption using the F-test for equality of variances. (Use a = 0.05.) State the...
Test using the p-value approach with ? = 0.05.State the null and alternative hypothesis.H0: ? < 98.6 versus Ha: ? > 98.6H0: ? = 98.6 versus Ha: ? > 98.6 H0: ? = 98.6 versus Ha: ? < 98.6H0: ? = 98.6 versus Ha: ? ≠ 98.6H0: ? ≠ 98.6 versus Ha: ? = 98.6Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)z=p-value=State your conclusion.The p-value is greater than alpha so H0 is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.The p-value is less than alpha so H0 is rejected. There is sufficient evidence to...