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6. Determine whether the following cell reaction is spontaneous or not at 25°C, and calculate a...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2 (0...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2 (0.12 M |Fe2 (0.0012 M) Fe(s) E2 =-0.440 V Efe/Fe = 0.339 V Cu2t/Cu Is the electrochemical cell spontaneous or not spontaneous Ecell V as written at 25 °C? not spontaneous spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2(0.0060 M), Sn4+(0.14 M) Fe3+(0.13 M), Fe2+(0.0056 M) Pt(s)...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2+ (0.15 M) Fe2+ (0.0039 M) Fe(s) E =-0.440 V E+Cu = 0.339 V Fe2+/Fe Is the electrochemical cell spontaneous or not spontaneous -0.779 Ecell = as written at 25 C? not spontaneous spontaneous о Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 'C Pt(s) Sn2 (0.0024 M), Sn4+ (0.12 M) |...
Calculate the Eo cell and indicate whether the reaction shown is spontaneous or nonspontaneous Calculate F...
Calculate the Eo cell and indicate whether the reaction shown
is spontaneous or nonspontaneous
Calculate F cell and indicate whether the overall reaction shown is spontaneous or none 1205) + 2e 21 (aq) Fº=0.53 V Craq) + 3e Cr(s) E=-0.74 V Overall reaction: 20/15) - 312(5) - 2013+ (aq) + (aq) + 61 (aq) Eºcell = -1.27 V. spontaneous Ecell -1.27 V, nonspontancous Eºcell - 1.27 V, spontaneous
38. The following redox half reactions are combined in a voltaic cell. Which reaction occurs at...
38. The following redox half reactions are combined in a voltaic cell. Which reaction occurs at the cathode and what is the Eceu? Fe2+(aq) + 2e → Fe(s) E°=-0.44 V Cu²+(aq) + 2e → Cu(s) E°= 0.34 V a) b) c) d) Cu2+(aq) + 2e → Cu(s), Ecell = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecel = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecell =-0.10 V Cu²+(aq) + 2e → Cu(s), Ecel = 0.10 V Cu²+ (aq) +...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Cu(s) Cu2+(0.14 M) | Fe2+(0.0044 M) Fe(s) Ecu?+Icu = 0.339 V Efez lfe = -0.440 V Ecell = v Is the electrochemical cell spontaneous or not spontaneous as written at 25 °C? O not spontaneous O spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2+(0.0048 M), Snº+(0.11 M) || Fe3+(0.12...
What would be the standard cell potential for a spontaneous electrochemical cell constructed with the two...
What would be the standard cell potential for a spontaneous electrochemical cell constructed with the two metals below? Cu2+(aq) + 2e– → Cu(s) E° = 0.34 V Sn4+(aq) + 2e– → Sn2+(aq) E° = 0.13 V
What would be the standard cell potential for a spontaneous electrochemical cell constructed with the two...
What would be the standard cell potential for a spontaneous electrochemical cell constructed with the two metals below? Cu2+(aq) + 2e– → Cu(s) E° = 0.34 V Sn4+(aq) + 2e– → Sn2+(aq) E° = 0.13 V
Calculate the cell potential for the reaction below when the concentrations of ions are: [Ag+ ]...
Calculate the cell potential for the reaction below when the concentrations of ions are: [Ag+ ] = 0.010 M and [Cu2+] = 0.750 M, at 25 °C. Cu(s) + 2Ag+ (aq) --> Cu2+(aq) + 2Ag(s) Given the standard reduction potentials: Cu2+(aq) + 2e– → Cu(s) Eϴ = 0.34 V Ag+ (aq) + e– → Ag(s) Eϴ = 0.80 V (A) 0.35 V (B) 0.44 V (C) 0.46 V (D) 0.48 V (E) 0.57 V
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 ∘ C . Cu ( s ) ∣ ∣ Cu 2 + ( 0.13 M ) ∥ ∥ Fe 2 + ( 0.0011 M ) ∣ ∣ Fe ( s ) E ∘ Cu 2 + / Cu = 0.339 V E ∘ Fe 2 + / Fe = − 0.440 V E cell = V
Answers and detailed explanations For the following electrochemical cell, calculate the potential and determine if the...
Answers and detailed explanations
For the following electrochemical cell, calculate the potential and determine if the cell reaction is spontaneous as written at 25 °C. Cu(s)|Cu2+(0.15 M)||Fe2+(0.0020 M)|Fe(s) Ecuaticu = 0.339 V Efez-ffe = -0.440 V Ecell = Determine if the cell reaction is spontaneous as written. O spontaneous O not spontaneous
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2 (0.12 M |Fe2 (0.0012 M) Fe(s) E2 =-0.440 V Efe/Fe = 0.339 V Cu2t/Cu Is the electrochemical cell spontaneous or not spontaneous Ecell V as written at 25 °C? not spontaneous spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2(0.0060 M), Sn4+(0.14 M) Fe3+(0.13 M), Fe2+(0.0056 M) Pt(s)...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2+ (0.15 M) Fe2+ (0.0039 M) Fe(s) E =-0.440 V E+Cu = 0.339 V Fe2+/Fe Is the electrochemical cell spontaneous or not spontaneous -0.779 Ecell = as written at 25 C? not spontaneous spontaneous о Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 'C Pt(s) Sn2 (0.0024 M), Sn4+ (0.12 M) |...
Calculate the Eo cell and indicate whether the reaction shown
is spontaneous or nonspontaneous
Calculate F cell and indicate whether the overall reaction shown is spontaneous or none 1205) + 2e 21 (aq) Fº=0.53 V Craq) + 3e Cr(s) E=-0.74 V Overall reaction: 20/15) - 312(5) - 2013+ (aq) + (aq) + 61 (aq) Eºcell = -1.27 V. spontaneous Ecell -1.27 V, nonspontancous Eºcell - 1.27 V, spontaneous
38. The following redox half reactions are combined in a voltaic cell. Which reaction occurs at the cathode and what is the Eceu? Fe2+(aq) + 2e → Fe(s) E°=-0.44 V Cu²+(aq) + 2e → Cu(s) E°= 0.34 V a) b) c) d) Cu2+(aq) + 2e → Cu(s), Ecell = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecel = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecell =-0.10 V Cu²+(aq) + 2e → Cu(s), Ecel = 0.10 V Cu²+ (aq) +...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Cu(s) Cu2+(0.14 M) | Fe2+(0.0044 M) Fe(s) Ecu?+Icu = 0.339 V Efez lfe = -0.440 V Ecell = v Is the electrochemical cell spontaneous or not spontaneous as written at 25 °C? O not spontaneous O spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2+(0.0048 M), Snº+(0.11 M) || Fe3+(0.12...
Answers and detailed explanations
For the following electrochemical cell, calculate the potential and determine if the cell reaction is spontaneous as written at 25 °C. Cu(s)|Cu2+(0.15 M)||Fe2+(0.0020 M)|Fe(s) Ecuaticu = 0.339 V Efez-ffe = -0.440 V Ecell = Determine if the cell reaction is spontaneous as written. O spontaneous O not spontaneous
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