the reaction is
part A
A2 +B2 AB3
since we see that in the product there are 3 blue atoms ans 1 red atoms so there are 3 B atoms and 1 A atom
no of A atoms on right side is 1 and on left side is 2 so multiply 2 on right side to balance the number of A atoms and the equation would look like
A2 +B2 2AB3
no of B atoms on right side is 2*3=6 atoms and on left side is 2 so multiply 3 on left side to balance the number of B atoms and the equation would look like
A2 +3B2 2AB3 : this the balance equation
part B
we see the stoichiometry of A2 is 1 ,of B2 is 3 and of AB3 is 2
in terms of moles
1 mole of A2 reacts with 3 moles of B2 to produce 2 moles of AB3
so
1 mole of A2 produces 2 moles of AB3
e following diagram represents the reaction of A2 (red heres) with B (blue spheres). (Figure 1)...
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