SOLUTION:
From given data,
A random sample
of 86 observations produced a mean
= 25.4 and a standard deviation s = 2.7.
sample size = n= 86
mean =
= 25.4
standard deviation = s = 2.7
Formula for for the population mean µ
Z
/2
(
/
)
(a) Find a 95%
confidence interval for
95% confidence interval
Confidence interval is 95%
95% = 95/100 = 0.95
= 1 - Confidence
interval = 1-0.95 = 0.05
/2 = 0.05 / 2
= 0.025
Z/2 =
Z0.025 = 1.96
for the population mean µ
Z
/2
(
/
)
Z0.025
(s /
)
25.4 1.96
(2.7 /
)
25.4 1.96
(2.7 / 9.2736 )
25.4 0.57065
(24.82935, 25.97065)
24.829 <
< 25.971
(b) Find a 90%
confidence interval for
90% confidence interval
Confidence interval is 90%
90% = 90/100 = 0.90
= 1 - Confidence
interval = 1-0.90 = 0.10
/2 = 0.10 / 2
= 0.05
Z/2 =
Z0.05 = 1.64
for the population mean µ
Z
/2
(
/
)
Z0.05
(s /
)
25.4 1.64
(2.7 /
)
25.4 1.64
(2.7 / 9.2736 )
25.4 0.477484
(24.922516, 25.877484)
24.923 <
< 25.877
(c) Find a 99%
confidence interval for
99% confidence interval
Confidence interval is 99%
99% = 99/100 = 0.99
= 1 - Confidence
interval = 1-0.99 = 0.01
/2 = 0.01 / 2
= 0.005
Z/2 =
Z0.005 = 2.57
for the population mean µ
Z
/2
(
/
)
Z0.05
(s /
)
25.4 2.58
(2.7 /
)
25.4 2.58
(2.7 / 9.2736 )
25.4 0.751164
(24.648836, 26.151164)
24.649 <
< 26.151
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