Question

b=0= 2 Na SnCl4 > 55°C dropwise addition within 30 min > 45 °C

Can you explain ( in words) the mechanism of the above scheme.

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Answer #1

Chlorobenzene, with Na at the given condition produces PhNa (C​​​​6H5Na). This follows the Single Electron Transfer(SET) mechanism, generating NaCl as the by product. PhNa then reacts with SnCl4, where Ph- (as a nucleophile) attacks the Sn-center and displaces the Cl- groups one by one, to form the product. The reaction is similar to the Wurtz-Fittig reaction.

Na +e Na Nacu Na Na +e Na Na 1 SN2 Simple mechanism 3PCu o Sn + Nacu Na u 33 Sn 3 Nacu + 4Hope that will resolve the problem :-)

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