Question

EXPERIMENT 25 REPORT SHEET Determination of the Dissociation Constant of a Weak Acid Trial 3 B. Standardization of Sodium Hydroxide (NaOH) Solution Trial 1 Trial 2 Mass of bottle + KHP Mass of bottle Mass of KHP used 0.503 0.545 Final buret reading Initial buret reading mL of NaOH used 26.90mL 1.OOML 20.40m 100mL Molarity of NaOH Average molarity (show calculations and standard deviation) Standard deviation (see Experiment 8)

Answer 1

KHP moles are calculated:

n KHP = g / MM = 0.503 g / 204.22 g / mol = 0.0025 mol

Trial 2: 0.0027 mol

The volume of NaOH used is calculated:

V NaOH = 26.9 - 1 = 25.9 mL

Trial 2: 27.4 mL

The molarity of NaOH is calculated:

M = n / V = ​​0.0025 mol / 0.0259 L = 0.097 M

Trial 2: 0.099 M

Average = (0.097 + 0.099) / 2 = 0.098 M

SD = 0.001 M

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