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8. Part A. (9 pt) For the reaction below, predict the signs for delta H system, delta S system, and delta S surrounding, AND explain your answer for each.

8. Part A. (9 pt) For the reaction below, predict the signs for AHºsys, ASºsys, and AS surr, and EXPLAIN your answers.

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Answer #1
  • The sign of ΔH°sys will be negative because

one double bond will be transformed to two single bonds that is why energy will be released in this process

  • The sign of ΔS°sys will be negative because

the number of reactant(s) (which is 2 ) is greater than the number of products ( which is 1) as a result entropy change will be negative.

  • ( ΔS°sys + ΔS°surr) = ΔS°total > 0 because the reaction is spontaneous so ΔS°surr have to be positive in sign as ΔS°sys is negative in sign.
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