Balanced chemical equation is:
NaOH + HBr ---> NaBr + H2O
Here:
M(NaOH)=0.15 M
V(NaOH)=18.8 mL
V(HBr)=25.0 mL
According to balanced reaction:
1*number of mol of NaOH =1*number of mol of HBr
1*M(NaOH)*V(NaOH) =1*M(HBr)*V(HBr)
1*0.15*18.8 = 1*M(HBr)*25.0
M(HBr) = 0.1128 M
Answer: 0.113 M
1) A 25.00 mL sample of HBr is titrated with a 0.150 M standardized sodium hydroxide...
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