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It is believed that nearsightedness affects about 8% of all children. In a random sample of 194 children, 21 are nearsighted.(d) What is the p-value for this hypothesis test? (please round to four decimal places) р- (e) What is the conclusion of the

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Answer #1

a )

H0: p = 0.08

Ha: p \neq 0.08

b)

sample proportion \hat{p} = 21 / 194 = 0.1082

c)

Test statistics

z = (\hat{p} - p) / SE

= (0.1082 - 0.08) / 0.0195

= 1.45

d)

p-value = 2 * P(Z > z)

= 2 * P(Z > 1.45)

= 2 * 0.0735

= 0.1470

e)

Since p >= \alpha , we do not have enough evidence to reject the null hypothesis.

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