Question

1b)Does the new treatment increase the mean survival period? Choose the appropriate hypotheses to test the claim.

It is generally agreed that a certain standard treatment yields a mean survival period of 4.2 years for cancer patient. A new treatment is administered to 60 patients and their duration of survival is recorded. The sample mean and standard deviation of the duration is 4.5 years and 0.8 years, respectively. Find the P-value for the test and state your conclusion at a 0.01. The P-value is 0.00 14; The decision: Reject Ho The P-value is 0.9981; The decision: Reject Ho The P-value is 0.9981; The decision: Accept Ho The P-value is 0.00 19; The decision: Accept Ho The P-value is 0.0019; The decision: Reject HO

Group of answer choices

a)H0 : \mu μ \ge ≥ 4.2 versus H\alpha α : \mu μ < 4.2

b) H0 : \mu μ \le ≤ 4.5 versus H\alpha α : \mu μ > 4.5

c)H0 : \mu μ \le ≤ 4.2 versus H\alpha α : \mu μ > 4.2

d)H0 : \mu μ = 4.2 versus H\alpha α : \mu μ \ne ≠ 4.2

e)H0 : x \ge ≥ 4.2 versus H\alpha α : x > 4.2

Answer 1

Given that, 7 = 4.5,0 = 0.8, n = 60 Null and the alternative hypothesis: H:u=4.2 H:U>4.2 Significance level, a = 0.01 Test statistic: X-u 4.5-4.2 0.8 V60 = 2.90 P-value: p=P(Z > 2) =1-P(Z < 2.90) =1-0(2.90) = 1-0.9981 = 0.0019 (Standard normal tables)

Decision rule: Reject H,, if psa otherwise do not reject H, . Since the p-value less than the level of significance, so we reject the null hypothesis at specified significance level. Conclusion: There is sufficient evidence to support the claim that the new treatment increase the mean survival period